Definition We can use Wasserstein metric in place of F-divergence to define a distance between two distributions $P$ and $Q$ both defined over the same space $X$.
The Wasserstein distance $W_p(P,Q)$ of order $p$ is defined as:
$$W_p(P,Q) = \left( \inf_{\gamma \in \Gamma(P,Q)} \mathbb{E}_{(x,y) \sim \gamma} [d(x,y)^p] \right)^{1/p}$$
where:
$\Gamma(P,Q)$ is the set of all possible joint distributions of $(x,y)$ where $x,y \in X$ with marginals $x \sim P$ and $y \sim Q$ (also called couplings) $\gamma(x,y)$ is a particular joint distribution chosen out of all possible joint distributions in $\Gamma(P,Q)$ that minimizes $\mathbb{E}_{(x,y) \sim \gamma} [d(x,y)^p]$ $d(x,y)$ is the metric (distance) between points $x$ and $y$ in the space $X$ $p \geq 1$ is the order of the Wasserstein distance. Common choices are $p=1$ (first-order Wasserstein distance) and $p=2$ (second-order Wasserstein distance). Properties of Wasserstein metric When $p=1$, the Wasserstein distance is equivalent to the Earth Mover’s Distance (EMD), because it can be interpreted as the minimum amount of work required to transform one distribution into another. When $p=2$, the Wasserstein distance is equivalent to the squared Euclidean distance. The Wasserstein distance is always finite, unlike the F-divergence, which can be infinite. The Wasserstein distance is a true metric, meaning it satisfies the triangle inequality. When KL divergence is $0$ then Wasserstein distance is $0$, but not vice versa. Proof for 5th property - KL divergence is 0 then Wasserstein distance is 0 To prove that when the KL divergence is 0, the Wasserstein distance is also 0, we start with the definitions of both metrics.
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